((–1x^2–2x–14)/(x+5)(x^2+4)) = ((A)/(x+5)) + ((Bx+C)/(x^2+4))
Now evaluate the indefinite integral.
*int* ((–1x^2–2x–14)/((x+5)(x^2+4))dx
If you can give me the answer to the integral as well as A,B,and C please?!
Find A, B, and C of the partial fraction decomposition.?
You find A = -1, B = 0, and C = -2. The integral is -ln|x + 5| - arctan(x/2) + K.
sweet pea
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