Write a c program that inputs one five digit number, separtes the number into its individual digits.?

i need to use integer division and the remainder operation. eg. if i type 42139 it should look like 4 2 1 3 9. help please!!!


x=52


52%10=2


52-2=50


50/10=5





117%100=17


117-17=100


100/100=1


below is my code so far


# include %26lt;stdio.h%26gt;


int main()


{


int a,b,c,d,e;


printf("enter 5 single digits\n");


scanf("%f%f%f%f%f", %26amp;a,%26amp;b,%26amp;c,%26amp;d,%26amp;e,)


a=%f





}

Write a c program that inputs one five digit number, separtes the number into its individual digits.?
Since you know it is 5 digits long you could:





1. Divide the input by 10000 (notice its 5 digits long as well). The reason being that in computers dividing integers always returns an integer then your result will be a whole # and so e.g., 42139 / 10000 = "4"





2. Subtract: your answer from #1 which is 1st multiplied by 10000 from the original 5-digit input e.g. 42139 - 40000 = 2139





3. Now, divide 2139 by 1000 (notice its 4 digits)...this gives you the answer of: "2"





2. Subtract: your answer from #3 which is 1st multiplied by 1000 from the 4-digit input mentioned in #2 e.g. 2139 - 2000 = 139





3. and so on....





It should be noted that the modulus (remainder operator could be used instead where i was multipying the result with the 10^x in the steps above...it was just merely preference for me)
Reply:Don't want to do your homework, but your code won't work, you need %d instead of %f. But as another poster said, why not scan it as a string and output it as chars?





char ins[80];


int c;





printf("enter a five digit number: ");


scanf("%s", ins); /* this will break if they enter %26gt; 80 */


for(c = 0; c %26lt; 5; c++){


putchar(ins[c]);


putchar(' '); /* that's a space between the quote marks */


}


putchar('\n');
Reply:I would read the number in as a string and then using the substr functions, i would retrieve each digit.





Good luck.