C++ little problem?

I'm having problem with this piece of code:





#include %26lt;stdio.h%26gt;





#include %26lt;conio,h%26gt;











void main( )





{





int y=0, r=0, c=8;





do{





clrscr( );





printf(“value:”); scanf(“%d ”, %26amp;y);





if (y = = 0)





r = r+1;





}while(y%26lt;=100);





printf(“ r = %d”, r);





}





****


ok, now my question is:


does this determine:


a) counts the number of zeros entered in n numbers that are lower than 101


b) counts the number of zeros entered in n numbers that are lower than 100





really having trouble with this, already did many tests but can't get to a conclusion, any help would be greatly appreciated.

C++ little problem?
Look at this from your program:





while(y%26lt;=100);





What this means is that the code in the loop will execute when the condition is true. In this case, the condition is that y is less than or equal to 100. So, when y is 100 the loop will still execute. But that is it. It will not work past 100. That means that it will count the numbers until it gets to 100 -100 will be counted.





So a) is the correct answer.
Reply:Choice a is the answer.
Reply:Entering in 100 would not get counted but the loop continues.





Entering 101 would not get counted and the loop would stop.





I would say both answers are correct. But, to stop the loop A would be the answer.





bad question though...if they are trying to teach while loop condition stops. Bad bad....